[最も選択された] (1-x^2)y'' 2xy'=0 y1=1 111978-(1 − x2)y'' + 2xy' = 0 y1 = 1

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1 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials information y = (sqrt(pi/2)erf(x) y_0)e^(x^2) We can use an integrating factor when we have a First Order Linear nonhomogeneous Ordinary Differential Equation of the form;

(1 − x2)y'' + 2xy' = 0 y1 = 1